Utility: 150KV, 1000 MVAsc
Transformer 1:
170 MVA, 150/13.8KV, 15% Z
13.8KV Bus
Generator:
100MVA, X"d = 0.2
Transformer 2:
30 MVA, 13.8/6.6KV, 15% Z
6.6KV Bus
Transformer 3:
2MVA, 6.6KV/400V, 10% Z
Motor 1:
10 MVA (Lumped), 20% Z
400V Bus
Motor
2: 1000 KVA (Lumped),
20% Z
Motor 3:
600 KVA (Lumped),
10% Z
In the event
of a
short circuit, the
sources of short circuit current are
1. Utility
2. Generators
3. Motors
Static loads such
as heaters and
lighting do not contribute
to short circuit.
Generators
So, here
are the results of MVAsc:
Utility: MVAsc = 1000MVA
Transformer 1:
MVAsc = 170 / 0.15 = 1133.33
MVA
13.8KV Bus
Generator:
MVAsc = 100 / 0.2 = 500 MVA
Transnformer 2:
MVAsc = 30 / 0.15 = 200 MVA
6.6KV Bus
Transformer 3:
MVAsc = 2 / 0.1 = 20 MVA
Motor 1:
MVAsc = 10 / 0.2 = 50 MVA
400V Bus
Motor 2:
MVAsc = 1 / 0.2 = 5 MVA
Motor 3:
MVAsc = 0.6 / 0.1 = 6 MVA
Now we calculate the upstream contribution :
At
Transformer 1:
MVAsc @ 150KV = 1000 MVA
MVAsc @ 13.8KV = 1/ (1 / 1000 + 1
/1133.33) = 531.25 MVA
At
Transformer 2:
MVAsc @ 13.8KV = 531.25 + 500 = 1031.25
MVA
MVAsc @ 6.6KV = 1/ (1 / 1031.25 + 1 / 200) = 167.51 MVA
At
Transformer 3:
MVAsc @ 6.6KV = 167.51 + 50 = 217.51
MVA
MVAsc @ 400V = 1/ (1 / 217.51 + 1 / 20)
= 18.31 MVA
At 400V
Motors
Motor 3: MVAsc = 18.31 x 5 / ( 5 + 6 )
= 8.3 MVA
Motor 4: MVAsc = 18.31 x 6 / ( 5 + 6 ) = 9.98 MVA
The fault MVAsc @bus 400V = 18.31 + 5 + 6 = 29.31MVAsc
The three
phase If =
29.31/(1.732*(0.4)) = 42.3 kA.
Now we come to fault single phase to ground :
For single phase faults, positive
sequence, negative sequence and zero sequence
impedances need to be calculated.
If = 3 (I1 + I2 + I0)
Examining the circuit in above, at the
400V Bus, on Transformer 3 contributes to the
zero sequence current.
For transformers, the negative
sequence and zero sequence impedance are equal to the positive sequence
impedance.
Z1 = Z2 = Z0 or
MVA1 = MVA2 = MVA0
@bus 400V;
1 / MVAsc =1/3 (1 / MVAsc1 + 1 /
MVAsc2 + 1 / MVAsc0)
1 / MVAsc = 1/3 (1 / 29.31 + 1 / 29.31
+ 1 / 20 )

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